Wednesday, 20 January 2016

quantum field theory - In QFT, why do fermions have to anticommute in order to insure causality?


I have seen this question and I believe I understand the answer to it. However, AFAIK, only for bosons the causality condition is a vanishing commutator. For fermions we expect the anticommutator $[\phi,\phi^\dagger]_+$ to turn zero. The answer given to the question above does not seem to address this.




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