When a person lifts a book while standing on the earth's surface. Why is his force considered external to the book-earth system? Isn't his force internal like the case of the forces that cause the exploson of a bomb. I think the forces the person exerts on both the book and the earth are internal since they are equal but opposite therefore resulting in the position of the centre of mass of the system being maintained and if i'm right is the mechanical energy of the system constant? Am i wrong? Please correct me.
Subscribe to:
Post Comments (Atom)
Understanding Stagnation point in pitot fluid
What is stagnation point in fluid mechanics. At the open end of the pitot tube the velocity of the fluid becomes zero.But that should result...
-
A rook stands in the lower left corner of an $m\times n$ chessboard. Alice and Bob alternately move the rook (horizontally or vertically, th...
-
I am researching Mercury's orbital precession. I have considered most perturbations and general relativity. I am still not satisfied. I ...
-
I am having trouble understanding how centripetal force works intuitively. This is my claim. When I have a mass strapped on a string and spi...
-
(The puzzle statement now identifies these numbers as equivalent.) O O ...
-
In this question/answer Does someone falling into a black hole see the end of the universe? , it is stated that an observer free falling tow...
-
Yesterday, I understood what it means to say that the moon is constantly falling (from a lecture by Richard Feynman ). In the picture below ...
-
A crime has been carried out by one person, there are 5 suspects. Each suspect is asked under polygraph who they think committed the crime. ...
No comments:
Post a Comment