Tuesday, 5 January 2016

homework and exercises - Electric potential of sphere


enter image description here


(a) I am a little confused about this part. The point at A to B isn't radial. The electric field is radially outward, but if I look at the integral


baEds=baρr3ϵ0ˆrds


The vector ds and r can't be in the same direction, so do I have to express it in norm form of the dot product? I am afraid to do so. So my wishful thinking answer (since it says it is 2 marks ) is


baEds=Rrρr3ϵ0dr


(b) Okay this one isn't too bad, but i am extremely paranoid. So I went back to the definition of potential


V=kdqd

Since the density is uniform, I simply get V=kQd


Now I just substitute r into equation and get V=kQr=Q4πϵ0r.


Note that "d" is the radial distance. I avoided using r or R becuase the picture uses r and R



Thank you for reading



Answer



Why are you looking for a radial surface..? Look it as an Equipotential surface (a surface where all points are at same constant electric potential) as it comes with sphere. Hence, you can assume the points A to B as radial to find the potential difference.


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