Saturday 11 June 2016

cipher - The door of death!


You have been taken prisoner and thrown in a dungeon. You have escaped your cell, are standing in front of two identical doors. One will lead you to freedom, the other to a place where you will die a painful death. Luckily, you have a friend that has agreed to help you. He has smuggled you a code inside of a fake record, but had to encode it in case of them finding out that he was helping their POW to escape, tracing who had sent it and taking him prisoner as well. The message reads this: 38 23 53 48; 38 23 53 50 --- 38 23 53 48; 38 23 54 53 --- 38 23 53 48; 38 23 54 55 --- 38 23 53 49; 38 23 54 55 --- 38 23 53 49; 38 23 53 50 Which door should you go through: Left or Right?


Note 1: This puzzle requires a certain degree of computer knowledge.


Note 2: This CJam program may help: q'[,65>Dm>_el+_$er



Answer



The initial decoding:



38 is ascii decimal for '&', and 23 is ascii hexadecimal for '#', which makes me think every 4 numbers are a html encoded ascii character (starting with "&#").

53 is ascii decimal for '5' and 48 is ascii decimal for '0', thus the first four numbers are "2", or the character '2'.



Proceeding the same way with all numbers we get:




The sequence 24 2A 2C 3C 34, which is hexadecimal scan code for a PS/2 keyboard (used in one of OP's previous puzzles).

The resulting characters are E V T U G.



Then applying ROT-13 results in the answer:



the R I G H T door.



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